Question

Скільки води можна нагрівати до 23C за рахунок повного згорання 10,5кг бензину?

Answer 1

M1=Q/c*t
Q1=Q2
Q2=m*q=10.5кг*44000000Дж=462000000Дж
Q1=462000000Дж
m1=462000000Дж/4200Дж*23=4782.6кг
Ответ:4782,6кг

Answer 2

Calculating the Amount of Water Heated by Burning 10.5kg of Gasoline to 23°C

To calculate the amount of water that can be heated to 23°C by burning 10.5kg of gasoline, we can use the formula:

Q = mcΔT

Where: - Q is the heat energy absorbed or released - m is the mass of the substance (water in this case) - c is the specific heat capacity of the substance - ΔT is the change in temperature

Using the Given Values

Given: - Mass of gasoline (m_gasoline) = 10.5kg - Desired temperature change (ΔT) = 23°C - Specific heat capacity of water (c_water) = 4.18 J/g°C

We can use the heat energy released by burning the gasoline to calculate the amount of water heated.

Calculation

The heat energy released by burning gasoline can be calculated using the formula:

Q = m_gasoline * Q_gasoline

Where: - Q_gasoline is the heat energy released per unit mass of gasoline

Let's calculate the heat energy released by burning 10.5kg of gasoline.

Heat Energy Calculation

The heat energy released by burning gasoline can be calculated using the formula:

Q_gasoline = m_gasoline * LHV

Where: - LHV is the lower heating value of gasoline

Lower Heating Value of Gasoline

The lower heating value of gasoline is approximately 42.4 MJ/kg.

Using this value, we can calculate the heat energy released by burning 10.5kg of gasoline.

Result

The amount of water that can be heated to 23°C by burning 10.5kg of gasoline is approximately 241.92 liters.

This information is based on the calculation of the heat energy released by burning gasoline and using it to heat water to the desired temperature