Question

Парашютист спускается равномерно со скоростью v= 0,5 м/с. В какой-то момент времени парашютист подбрасывает вертикально вверх небольшое тело с начальной скоростью v0 = 4,5 м/с относительно себя. Какое расстояние окажется между парашютистом и телом, находящимся в высшей точке своего полета?

Answer 1

Найбольшая высота, которую достигнет тело h1=v*v/2*g=1,03 м, время полета тела t= корень(2*h/g)=0,46 с. За это время парашютист пролетит расстояние h2=v0*t=0.5*0.46=0.23. Расстояние  между телом и парашютистом h=h1+h2=1.26 м.

Answer 2

Calculation of the Distance between the Parachutist and the Object

To calculate the distance between the parachutist and the object when it reaches its highest point, we need to consider the motion of both the parachutist and the object.

Given: - Parachutist's descent speed: v = 0.5 m/s - Initial speed of the object thrown vertically upwards by the parachutist: v0 = 4.5 m/s

To find the distance between the parachutist and the object at the highest point of its flight, we can use the following equation:

d = (v^2 - v0^2) / (2g)

Where: - d is the distance between the parachutist and the object at the highest point - v is the parachutist's descent speed - v0 is the initial speed of the object thrown vertically upwards - g is the acceleration due to gravity (approximately 9.8 m/s^2)

Substituting the given values into the equation, we have:

d = (0.5^2 - 4.5^2) / (2 * 9.8)

Calculating this expression gives us the distance between the parachutist and the object at the highest point of its flight.

Let's calculate it:

d = (0.25 - 20.25) / 19.6

d = -20 / 19.6

d ≈ -1.02 meters

The negative sign indicates that the object is below the parachutist at the highest point of its flight. Therefore, the distance between the parachutist and the object is approximately 1.02 meters.

Please note that the negative sign indicates the direction of the distance, not the actual distance itself. The actual distance is always positive.