Question

Даю 15 баллов СРОЧНО Соня уронила в речку мячик объёмом 1,1 л. Какая сила Архимеда действует на мячик, если он погружён в воду только наполовину? Плотность воды 1000 кг/м3. Ответ: _____________________________ Н.

Answer 1

Ответ:

5Н

Объяснение:

FАрхимеда=pVg

V - объем той части мяча, которая находится под водой

1 л =1 *10^-3 м^3

F = 1000 кг/м^3 x 0,5*10^-3 м^3 x 10Н/кг = 5Н

Answer 2

Calculating the Force of Archimedes on the Half-Submerged Ball

When a ball is submerged in water, the force of Archimedes can be calculated using the formula:

F = ρ * g * V

Where: - F is the force of Archimedes - ρ is the density of the fluid (in this case, water) - g is the acceleration due to gravity - V is the volume of the fluid displaced by the submerged object

Given: - Density of water (ρ) = 1000 kg/m^3 - Volume of the ball (V) = 1.1 L = 0.0011 m^3 (since 1 L = 0.001 m^3) - The ball is submerged halfway, so the volume of water displaced is half of the total volume of the ball, which is 0.00055 m^3

Calculating the Force of Archimedes

Using the formula, we can calculate the force of Archimedes acting on the ball:

F = ρ * g * V F = 1000 kg/m^3 * 9.81 m/s^2 * 0.00055 m^3

Calculating the value: F ≈ 5.39 N

Therefore, the force of Archimedes acting on the half-submerged ball is approximately 5.39 N.