Question

Луч света от лазерной указки, находящейся на дне аквариума, падает на горизонтальную поверхность воды. Чему равен угол преломления, если угол падения равен 30 градусов?

Answer 1

Ответ:

=22градусов Ну по-моему как-то так эсли что пере проверь

Answer 2

Calculation of the Angle of Refraction

When a laser beam from a laser pointer placed at the bottom of an aquarium passes through the horizontal surface of the water, it undergoes refraction. The angle of incidence is the angle between the incident beam and the normal to the water surface, and the angle of refraction is the angle between the refracted beam and the normal to the water surface.

Given that the angle of incidence is 30 degrees, we can calculate the angle of refraction using Snell's law, which states that the ratio of the sines of the angles of incidence and refraction is equal to the ratio of the velocities of light in the two media:

n1 * sin(θ1) = n2 * sin(θ2)

Where: - n1 is the refractive index of the medium the light is coming from (in this case, air) - θ1 is the angle of incidence - n2 is the refractive index of the medium the light is entering (in this case, water) - θ2 is the angle of refraction

The refractive index of air is approximately 1, and the refractive index of water is approximately 1.33.

Plugging in the values, we get:

1 * sin(30) = 1.33 * sin(θ2)

Simplifying the equation, we find:

sin(θ2) = (1 * sin(30)) / 1.33

Using a calculator, we can find the value of sin(θ2) to be approximately 0.449.

To find the angle of refraction, we take the inverse sine (sin^(-1)) of 0.449:

θ2 ≈ sin^(-1)(0.449)

Using a calculator, we find that the angle of refraction is approximately 27.3 degrees.

Therefore, the angle of refraction, when the angle of incidence is 30 degrees, is approximately 27.3 degrees