Question

Для піднімання тіла масою 90 кг на висоту 2 м використали похилу площину довжиною 6 м. При рівномірному переміщенні тіла до нього прикладали силу 400 Н. Визначити ККД похилої площини.

Answer 1

Ответ:

0,75

Объяснение:

400×6=2400 90×10×2=1800 1800:2400=0,75

Answer 2

Calculation of Efficiency of Inclined Plane

To determine the efficiency of the inclined plane, we need to calculate the work input and work output.

Given: - Mass of the body (m) = 90 kg - Height (h) = 2 m - Length of the inclined plane (l) = 6 m - Force applied (F) = 400 N

Calculation:

The work input (W_in) is given by the formula:

W_in = F * l

Substituting the given values:

W_in = 400 N * 6 m

Calculating the work input:

W_in = 2400 J

The work output (W_out) is given by the formula:

W_out = m * g * h

where g is the acceleration due to gravity (approximately 9.8 m/s^2).

Substituting the given values:

W_out = 90 kg * 9.8 m/s^2 * 2 m

Calculating the work output:

W_out = 1764 J

The efficiency (η) of the inclined plane is given by the formula:

η = (W_out / W_in) * 100%

Substituting the calculated values:

η = (1764 J / 2400 J) * 100%

Calculating the efficiency:

η ≈ 73.5%

Therefore, the efficiency of the inclined plane is approximately 73.5%.