Question

ПОМОГИТЕ ПОЖАЛУЙСТА!!! Сергiйко вирішив зробити плот з дитячого надувного круга для плавання. Сергiйко надув круг і поклав на нього дошку масою 2 кг. Для того щоб дізнатися, вантаж якоï маси може перевозити на собі такий плiт, Сергій почав по одній ставити на дошку дволітрові пляшки з водою (маса однієї пляшки також дорівнює 2 кг). Виявилося, що круг повністю занурився у воду тоді, коли на дошку було поставлено 4 пляшки. Чому дорівнює об'єм надувного круга? Густина води 1000 кг/м, прискорення вільного падіння дорівнює 10 Н/кг. Відповідь дайте у м³.​

Answer 1

Відповідь: 0,01 м³

Пояснення:

Answer 2

Problem Analysis

Sergiyko wants to determine the volume of an inflatable circle (swim ring) by placing a 2 kg board on it and adding two-liter bottles filled with water until the circle is completely submerged. The question asks for the volume of the inflatable circle.

Solution

To solve this problem, we need to consider the buoyant force acting on the submerged board. The buoyant force is equal to the weight of the water displaced by the submerged object. When the board is completely submerged, the buoyant force is equal to the weight of the board.

We can use the equation for the buoyant force:

Buoyant force = weight of the water displaced

The weight of the water displaced is equal to the weight of the board:

Weight of the water displaced = weight of the board

Since the weight of the board is given as 2 kg, we can calculate the weight of the water displaced.

Next, we need to calculate the volume of the water displaced. We can use the equation:

Volume of water displaced = weight of the water displaced / density of water

The density of water is given as 1000 kg/m³.

Finally, we can calculate the volume of the inflatable circle by subtracting the volume of the water displaced from the total volume of the bottles.

Let's calculate the volume step by step.

Calculation

1. Calculate the weight of the water displaced: - The weight of the board is given as 2 kg. - Therefore, the weight of the water displaced is also 2 kg.

2. Calculate the volume of the water displaced: - The density of water is given as 1000 kg/m³. - Using the equation: Volume of water displaced = weight of the water displaced / density of water - Substituting the values: Volume of water displaced = 2 kg / 1000 kg/m³ = 0.002 m³

3. Calculate the volume of the inflatable circle: - The volume of each bottle is given as 2 liters, which is equal to 0.002 m³. - When 4 bottles are placed on the board, the volume of water displaced is equal to the volume of the inflatable circle. - Therefore, the volume of the inflatable circle is 4 * 0.002 m³ = 0.008 m³.

Answer

The volume of the inflatable circle is 0.008 m³.

[[1]]