Question

Дитячий пістолет зарядили кулькою, яка має масу 10 г, при цьому пружина стислась на 5 см. Вистріливши вертикально вгору, кулька піднялась на деяку висоту. Обчисліть цю висоту, якщо відомо, що жорсткість пружни 400 Н/м СРОЧНО ПЖ НАДО!!!!!!!​

Answer 1

Ответ: 100м

Объяснение:

Дано:

k=400Н/м

х=5см=0,05м

m=10г=0,01кг

g=10Н/кг

-----------------

h-?

В момент выстрела потенциальная энергия пружины превращается в кинетическую энергию шарика:

kx²/2=mV²/2

Отсюда скорость вылета шарика равна:

V=√(kx²/m)=√(400*0,05/0,01)=44,72м/с

Высоту подъема шарика находим по формуле:

h=V²/2g=44,72²/(2*10)=100м

Answer 2

Відповідь:

Объяснение:

Дано:

k=400Н/м

х=5см=0,05м

m=10г=0,01кг

g=10Н/кг

-----------------

h-?

В момент выстрела потенциальная энергия пружины превращается в кинетическую энергию шарика:

kx²/2=mV²/2

Отсюда скорость вылета шарика равна:

V=√(kx²/m)=√(400*0,05/0,01)=44,72м/с

Высоту подъема шарика находим по формуле:

h=V²/2g=44,72²/(2*10)=100м

Пояснення:

Answer 3

To calculate the height to which the bullet rises after being shot vertically upwards, we can use the principle of conservation of mechanical energy. The initial potential energy stored in the compressed spring is converted into kinetic energy of the bullet as it is released, and then into gravitational potential energy as it rises.

Given information:

- Mass of the bullet (m) = 10 g = 0.01 kg - Compression of the spring (x) = 5 cm = 0.05 m - Spring constant (k) = 400 N/m

Calculating the potential energy stored in the spring:

The potential energy stored in a compressed spring is given by the formula: PE = (1/2)kx^2.

Substituting the given values: PE = (1/2) * 400 N/m * (0.05 m)^2 PE = 0.5 * 400 N/m * 0.0025 m^2 PE = 0.5 * 1 N * 0.0025 m^2 PE = 0.00125 J

Calculating the maximum height reached by the bullet:

The potential energy stored in the spring is converted into gravitational potential energy when the bullet reaches its maximum height. The formula for gravitational potential energy is: PE = mgh, where m is the mass, g is the acceleration due to gravity, and h is the height.

Rearranging the formula, we get: h = PE / (mg).

Substituting the values: h = 0.00125 J / (0.01 kg * 9.8 m/s^2) h = 0.00125 J / 0.098 N h ≈ 0.0128 m

Therefore, the bullet rises to a height of approximately 0.0128 meters (or 12.8 centimeters).

Please note that this calculation assumes ideal conditions and neglects factors such as air resistance.

Answer 4

To calculate the height to which the bullet rises after being shot vertically upwards, we can use the principles of conservation of mechanical energy. The initial potential energy stored in the compressed spring is converted into kinetic energy of the bullet as it is released, and then into gravitational potential energy as the bullet rises.

Given information:

- Mass of the bullet (m) = 10 g = 0.01 kg - Compression of the spring (x) = 5 cm = 0.05 m - Spring constant (k) = 400 N/m

Calculating the height:

1. Calculate the potential energy stored in the compressed spring using Hooke's Law: - Potential energy (PE) = (1/2) * k * x^2

2. Calculate the initial kinetic energy of the bullet using the principle of conservation of mechanical energy: - Initial kinetic energy (KE) = PE

3. Calculate the velocity of the bullet using the equation for kinetic energy: - KE = (1/2) * m * v^2 - Solve for v: v = sqrt((2 * KE) / m)

4. Use the equation for projectile motion to calculate the maximum height reached by the bullet: - Maximum height (h) = (v^2) / (2 * g) - Where g is the acceleration due to gravity (approximately 9.8 m/s^2)

Let's calculate the height using these steps:

1. Calculate the potential energy stored in the compressed spring: - PE = (1/2) * 400 N/m * (0.05 m)^2 = 0.5 J

2. Calculate the initial kinetic energy of the bullet: - KE = 0.5 J

3. Calculate the velocity of the bullet: - v = sqrt((2 * 0.5 J) / 0.01 kg) ≈ 10 m/s

4. Calculate the maximum height reached by the bullet: - h = (10 m/s)^2 / (2 * 9.8 m/s^2) ≈ 5.1 m

Therefore, the bullet rises to a height of approximately 5.1 meters.