Question

Маша подкидывает у самой земли яблоко вверх, и через 5 с оно падает на землю. Чему равна скорость яблока у самой земли в момент падения? (м/с)​

Answer 1

Ответ:

25 м/с

Объяснение:

t=5 c    v=?

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Время падения t/2

v=g*t/2=10*5/2=25 м/с

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Answer 2

Calculation of the velocity of the apple at the moment of falling

To calculate the velocity of the apple at the moment it hits the ground, we need to consider the acceleration due to gravity. In this case, we can assume that the apple is in free fall, and the only force acting on it is gravity.

The acceleration due to gravity on Earth is approximately 9.8 m/s^2. This means that every second, the velocity of an object in free fall increases by 9.8 meters per second.

Since the apple is thrown upwards and then falls back down, we need to consider the time it takes for the apple to reach its highest point and then fall back down. Let's assume that it takes a total of 5 seconds for the apple to complete this motion.

During the first half of the motion, the apple is moving upwards against the force of gravity, so its velocity decreases. At the highest point, the velocity becomes zero. During the second half of the motion, the apple falls back down, and its velocity increases.

To find the velocity of the apple at the moment it hits the ground, we can use the following equation:

v = u + at

Where: - v is the final velocity (which we want to find) - u is the initial velocity (which is the velocity at the highest point, and is equal to zero) - a is the acceleration due to gravity (which is -9.8 m/s^2, considering the downward direction) - t is the time taken for the apple to fall (which is 5 seconds)

Plugging in the values, we get:

v = 0 + (-9.8) * 5

Simplifying the equation, we find:

v = -49 m/s

Therefore, the velocity of the apple at the moment it hits the ground is -49 m/s. The negative sign indicates that the velocity is directed downwards.

Please note that this calculation assumes ideal conditions and neglects factors such as air resistance.