Question

С какой высоты упало тело, если за последнюю секунду своего падения оно прошло путь = 24,5 м

Answer 1

H= g*t^2/2

по условию Δh= h(t) -h(t-Δt)
24,5=9,8*t²/2- 9,8*(t-1)²/2
24,5=9,8t -4,9
t=29,4/9,8=3 с
h=9,8*9/2=44,1 м - искомая высота

проверка h(2)=9,8*4/2=19,6 м
Δh=44,1-19,6=24,5 м соответствует условию

Answer 2

Calculating the Height of the Fall

To calculate the height from which the body fell, we can use the formula for distance traveled under constant acceleration:

s = ut + (1/2)at^2

Where: - s = distance traveled - u = initial velocity - a = acceleration (in this case, due to gravity, approximately 9.81 m/s^2) - t = time

Given that the body traveled a distance of 24.5 meters in the last second of its fall, we can use this information to calculate the height from which it fell.

Calculation

Using the formula s = ut + (1/2)at^2, and assuming the body fell from rest (u = 0), we can solve for the time it took to fall the last 24.5 meters.

24.5 = 0 + (1/2)(9.81)t^2

Solving for t, we get:

t = sqrt((2 * 24.5) / 9.81) ≈ 2.23 seconds

Now that we have the time, we can calculate the height from which the body fell using the formula s = ut + (1/2)at^2.

s = 0 + (1/2)(9.81)(2.23)^2 ≈ 24.5 meters

So, the body fell from a height of approximately 24.5 meters.