Question

В баллоне находится масса m1=10кг газа при давлении р1=10 МПа. Какую массу газа взяли из баллона,если давление стало равным р2=2,5 МПа? Температуру газа считать постоянной.

Answer 1

Задача не прошла... Глюк заколебал уже. Набираю по-второй. Буду краток...

p₁·V = m₁/M · R·T

p₂·V = m₂/M · R·T

p₁/m₁ = p₂/m₂

p₁/m₁ = p₂/ (m₁ - Δm)

 

m₁/p₁ = (m₁ - Δm) /p₂

m₁/p₁ = m₁/p₂ - Δm/p₂

Δm = m₁·(1 - p₂/p₁)

Δm = 7,5 кг

Answer 2

Calculation of the Mass of Gas Taken from the Cylinder

To calculate the mass of gas taken from the cylinder, we can use the ideal gas law equation, which states that the product of pressure (P) and volume (V) is directly proportional to the number of moles of gas (n) and the gas constant (R), and inversely proportional to the temperature (T). Mathematically, it can be expressed as:

PV = nRT

Given that the temperature of the gas is constant, we can rewrite the equation as:

P1V1 = P2V2

Where: - P1 is the initial pressure of the gas (10 MPa) - V1 is the initial volume of the gas (unknown) - P2 is the final pressure of the gas (2.5 MPa) - V2 is the final volume of the gas (unknown)

We can rearrange the equation to solve for V2:

V2 = (P1 * V1) / P2

Since the mass of the gas (m) is directly proportional to the volume (V), we can write:

m1 / V1 = m2 / V2

Where: - m1 is the initial mass of the gas (10 kg) - m2 is the final mass of the gas (unknown)

Rearranging the equation to solve for m2:

m2 = (m1 * V2) / V1

Now, let's substitute the given values into the equation:

P1 = 10 MPa V1 = unknown P2 = 2.5 MPa V2 = (P1 * V1) / P2

m1 = 10 kg m2 = (m1 * V2) / V1

To find the value of V2, we need to know the initial volume of the gas or have additional information. Unfortunately, the given information does not provide the initial