Question

На тело обьемом 120см3 полностью погруженное в жидкость, действует архимедова сила 0,96 Н. какова плотность жидкости?

Answer 1

Формула Fарх= q жидкости * V тела * g
Сначала переводим 120 см^3 = 0.00012  м^3
g= 10Н/кг

q жидкости = Fарх/V тела * g

Вычисление: 0,96Н/(10Н/кг*0,00012м^3) = 800 кг/м^3

Answer 2

Calculating the Density of the Liquid

To calculate the density of the liquid, we can use the formula for the Archimedes' principle, which states that the buoyant force acting on an object immersed in a fluid is equal to the weight of the fluid displaced by the object. The buoyant force can be calculated using the formula:

F = ρVg

Where: - F is the buoyant force, - ρ is the density of the liquid, - V is the volume of the liquid displaced by the object, and - g is the acceleration due to gravity.

Given: - Volume of the object (V) = 120 cm^3 - Buoyant force (F) = 0.96 N

We can rearrange the formula to solve for the density (ρ):

ρ = F / Vg

Substitute the given values: ρ = 0.96 N / (120 cm^3 * g)

Calculating the Value of g

The acceleration due to gravity (g) is approximately 9.81 m/s^2. Converting this to cm/s^2: g = 9.81 m/s^2 = 981 cm/s^2

Calculating the Density

Substitute the value of g into the formula: ρ = 0.96 N / (120 cm^3 * 981 cm/s^2)

Now, we can calculate the density of the liquid using the given values.

ρ = 0.96 N / (120 cm^3 * 981 cm/s^2)

The density of the liquid is approximately 0.0000655 g/cm^3.