Question

50Балов даю!!! Физика!!!Автомобіль масою 1000 кг рухався зі швидкістю 36 км/год, починає гальмувати. Визначте силу тертя та шлях, який проходить автомобіль до зупинки, якщо коефіцієнт тертя 0,5 (приклад відповіді: 500;12)

Answer 1

Ответ:

47

Объяснение:

Все очень элементарно Берем формулу Кинетической энергеи тела

E кин = m ⋅ v 2 2 .

Переводим 1000кг в метры = 50 милиметров

Зная коэфицент потери массы по времени, мы можем посчитать 1000/50=56мм

Коэфицент от 56 - 0,5= 55,5

В году 365 дней, на каждого человека в семьи приходится 1 каляска. У коляски 6 колес. Умножим 55,5 на 6 колес = 333 Из этого мы вычитваем 286 секунд в метре получаем 47. Ответ 47

Answer 2

Calculation of Frictional Force and Stopping Distance

To calculate the frictional force and stopping distance of a car, we need to use the following information:

- Mass of the car (m): 1000 kg - Initial velocity (v): 36 km/h - Coefficient of friction (μ): 0.5

First, let's convert the initial velocity from km/h to m/s:

Initial velocity (v) = 36 km/h = 10 m/s

Next, we can calculate the frictional force (F) using the formula:

F = μ * m * g

where: - μ is the coefficient of friction - m is the mass of the car - g is the acceleration due to gravity (approximately 9.8 m/s^2)

Substituting the given values into the formula:

F = 0.5 * 1000 kg * 9.8 m/s^2 = 4900 N.

Therefore, the frictional force acting on the car is 4900 N.

To calculate the stopping distance (d), we can use the equation:

v^2 = u^2 + 2ad

where: - v is the final velocity (which is 0 m/s since the car comes to a stop) - u is the initial velocity - a is the acceleration - d is the stopping distance

Rearranging the equation to solve for d:

d = (v^2 - u^2) / (2a)

Substituting the given values:

d = (0^2 - 10^2) / (2 * (-a))

Since the car is decelerating, the acceleration (a) will be negative. The negative sign indicates that the acceleration is in the opposite direction to the initial velocity.

Now, we need to find the acceleration (a) using the formula:

F = ma

Rearranging the equation to solve for a:

a = F / m

Substituting the known values:

a = 4900 N / 1000 kg = 4.9 m/s^2

Substituting the values of u, v, and a into the equation for d:

d = (0^2 - 10^2) / (2 * (-4.9 m/s^2))

Simplifying the equation:

d = -100 m^2/s^2 / (-9.8 m/s^2) = 10.2 m

Therefore, the stopping distance of the car is approximately 10.2 meters.

To summarize: - The frictional force acting on the car is 4900 N. - The stopping distance of the car is approximately 10.2 meters.

Please note that these calculations assume ideal conditions and do not take into account other factors such as air resistance or variations in the coefficient of friction.