Question

Тело упало с высоты 200м. Найти время падения и скорость в момент удара о землю

Answer 1

h=200 м

t,v=?

 

h=gt²/2

g≈10 м/с²

200=10t²/2

400=10t²

t²=40

t=√40=2√10 с≈6,3 с

 

g=v/t

10=v/2√10

v=20√10 с≈63,2 м/с² 

Answer 2

$h=\frac{gt^2}{2},\ \ \ \ \ v=gt.$

Из первого уравнения находим время падения, а затем из второго - конечную скорость:

$t=\sqrt{\frac{2h}{g}}=\sqrt{\frac{2*200}{9,8}}\ \approx\ 6,4\ c;\ \ \ v=gt=9,8*6,4= 62,7\ m/c.$

Ответ: 6,4 с;  62,7 м/с.

Answer 3

Calculation of Time of Fall and Impact Velocity

To find the time of fall and the velocity at the moment of impact, we can use the equations of motion and the principles of free fall.

The equation for the time of fall is given by:

t = sqrt((2h) / g)

where: - t is the time of fall - h is the height from which the object falls - g is the acceleration due to gravity (approximately 9.8 m/s^2)

In this case, the height from which the object falls is 200 meters. Plugging in the values, we get:

t = sqrt((2 * 200) / 9.8) = sqrt(400 / 9.8) ≈ 6.42 seconds.

The equation for the impact velocity is given by:

v = gt

where: - v is the impact velocity - g is the acceleration due to gravity - t is the time of fall

Plugging in the values, we get:

v = 9.8 * 6.42 ≈ 62.92 m/s.

Therefore, the time of fall is approximately 6.42 seconds, and the velocity at the moment of impact is approximately 62.92 m/s.