Question

десять паралельно з'єднаних ламп опором 0,5 кОм, кожна з яких розрахована на напругу 120 В, живляться через реостат від мережі з напругою 220 В. Яка потужність електричного струму в реостаті?

Answer 1

Напряжение на реостате 220-120=100В,
ток 1й лампы 120В/50Ом=2.4А, 10ти ламп 24А, этот же ток через реостат, тогда мощность на реостате 24*100= 2400Вт=2.4кВт

Answer 2

Calculation of Power in the Rheostat

To calculate the power in the rheostat, we need to determine the current flowing through it. We can use Ohm's Law to find the current:

Ohm's Law: V = I * R

Where: - V is the voltage across the rheostat (220 V) - I is the current flowing through the rheostat (to be determined) - R is the resistance of the rheostat (0.5 kΩ or 500 Ω)

Rearranging the equation, we can solve for I:

I = V / R

Substituting the given values:

I = 220 V / 500 Ω

Calculating the value:

I ≈ 0.44 A

Now that we have the current flowing through the rheostat, we can calculate the power using the formula:

Power (P) = Current (I) * Voltage (V)

Substituting the values:

P = 0.44 A * 220 V

Calculating the value:

P ≈ 96.8 W

Therefore, the power of the electric current in the rheostat is approximately 96.8 Watts.