Question

B=0.34Тл I=14.5A F=1.65H sin= 30 l=?

Answer 1

Сила Ампера:
F = B*I*L*sin(a)

L= F / (B*I*sin(a))

L= 1.65H / ( 0.34Тл * 14.5A * 0,5 ) = 0,67 м 

Ответ: 0,67 м.

Answer 2

To calculate the length (l) of a conductor carrying a current (I) of 14.5 amperes in a magnetic field (B) of 0.34 teslas, where the force (F) experienced by the conductor is 1.65 newtons and the angle (θ) between the magnetic field and the conductor is 30 degrees, you can use the formula for the magnetic force on a current-carrying wire in a magnetic field:

F = B * I * l * sin(θ)

You're given B, I, F, and θ, and you want to solve for l.

1. Convert the angle θ from degrees to radians, as the sin function typically uses radians. There are π radians in 180 degrees, so:

θ = 30 degrees * (π radians / 180 degrees) = π/6 radians

2. Plug in the values into the formula:

1.65 N = (0.34 T) * (14.5 A) * l * sin(π/6)

3. Solve for l:

l = 1.65 N / [(0.34 T) * (14.5 A) * sin(π/6)]

Now, calculate the value of sin(π/6):

sin(π/6) = 0.5

Now, substitute the values and solve for l:

l = 1.65 N / [(0.34 T) * (14.5 A) * 0.5]

l ≈ 0.207 meters

So, the length (l) of the conductor is approximately 0.207 meters.