Question

На какой высоте над поверхностью Земли скорость искусственного спутника, движущегося по круговой орбите, должна составлять 7,75 км/с? Радиус Земли принять равным 6400 км; считать на поверхности Земли g=10 м/c^2? ПОДРОБНО КТО МОЖЕТ,ОЧЕНЬ НАДО ,ОЦЕНКА ЗА ЧЕТВЕРТЬ ЗАВИСИТ ОТ ЭТОЙ ЗАДАЧИ!!!!

Answer 1

На какой высоте над поверхностью 

Answer 2

Calculating the Orbital Velocity of a Satellite

To calculate the orbital velocity of a satellite moving in a circular orbit at a certain height above the Earth's surface, we can use the formula for orbital velocity:

Orbital velocity (v) = √(g * R)

Where: - v = orbital velocity - g = acceleration due to gravity - R = radius of the orbit (Earth's radius + height of the satellite)

Given: - Radius of the Earth (R_earth) = 6400 km - Acceleration due to gravity (g) = 10 m/s² - Desired height of the satellite (H) = ? - Desired orbital velocity (v) = 7.75 km/s

We can use the above formula to solve for the height of the satellite.

Calculating the Height of the Satellite

First, we need to convert the given values to a consistent unit. Let's convert the desired orbital velocity to m/s:

7.75 km/s = 7750 m/s

Now, we can use the formula to calculate the height of the satellite:

v = √(g * (R_earth + H))

7750 = √(10 * (6400 + H))

Solving for H:

7750² = 10 * (6400 + H)

60062500 = 64000 + 10H

10H = 60062500 - 64000

10H = 59998500

H = 5999850 km

So, the height of the satellite should be approximately 5999.85 km above the Earth's surface to achieve an orbital velocity of 7.75 km/s.

This calculation is based on the provided values and the formula for orbital velocity. If you have any further questions or need additional assistance, feel free to ask!