Question

скоростной поезд , отходя от станции , разгоняется и , находится на расстоянии 2 км от станции , начинает двигаться равномерно и прямолинейно со скоростью 108 км / ч . Чему равно время равномерного движения поезда , если на расстоянии 11 км от станции его скорость стала уменьшаться?

Answer 1

1) 11-2=9км - поезд ехал равномерно

2) 9/108=0,84(примерно) - часа поезд ехал равномерно

Answer 2

Problem Analysis

We are given the following information: - A high-speed train starts accelerating and is located 2 km away from the station. - The train then starts moving uniformly and linearly at a speed of 108 km/h. - We need to find the time it takes for the train to travel a distance of 11 km from the station when its speed starts decreasing.

Solution

To solve this problem, we can use the formula for calculating time:

time = distance / speed

Let's break down the problem into two parts:

1. Calculating the time it takes for the train to travel the initial 2 km: - The train is accelerating, so we don't have a constant speed. - We don't have enough information to calculate the time for this part.

2. Calculating the time it takes for the train to travel the remaining 11 km: - The train is moving uniformly and linearly at a speed of 108 km/h. - We can use the formula time = distance / speed to calculate the time for this part.

Let's calculate the time for the second part:

time = distance / speed = 11 km / 108 km/h

Now, let's calculate the time for the second part:

time = 11 km / 108 km/h = 0.1019 hours

To convert the time to minutes, we can multiply it by 60:

time = 0.1019 hours * 60 minutes/hour = 6.11 minutes

Therefore, the time it takes for the train to travel a distance of 11 km from the station when its speed starts decreasing is approximately 6.11 minutes.

Please let me know if I can help you with anything else.