Question

Кокосовый орех массой 8 кг падает с пальмы. Найдите его кинетическую энергию через 1 с после начала падения.

Answer 1

Eк=(mv^2)/2 
v=v0+at, в данном случае v=gt 
Eк=(m(gt)^2)/2
Eк=400 Дж

Answer 2

Calculation of Kinetic Energy

To calculate the kinetic energy of the coconut falling from a palm tree, we need to know the mass of the coconut and its velocity after 1 second of falling.

Given: - Mass of the coconut (m) = 8 kg To find the velocity after 1 second of falling, we need to consider the acceleration due to gravity. The acceleration due to gravity is approximately 9.8 m/s^2.

Using the equation of motion:

v = u + at

where: - v is the final velocity - u is the initial velocity (which is 0 in this case, as the coconut starts from rest) - a is the acceleration due to gravity (9.8 m/s^2) - t is the time (1 second)

Substituting the values into the equation, we can find the final velocity:

v = 0 + (9.8 m/s^2) * (1 s) = 9.8 m/s

Now that we have the mass (m = 8 kg) and the velocity (v = 9.8 m/s), we can calculate the kinetic energy (KE) using the formula:

KE = (1/2) * m * v^2

Substituting the values into the equation, we can find the kinetic energy:

KE = (1/2) * (8 kg) * (9.8 m/s)^2 = 313.6 Joules

Therefore, the kinetic energy of the coconut after 1 second of falling is approximately 313.6 Joules.

Please note that the above calculation assumes no air resistance or other external factors affecting the motion of the coconut.