Question

поезд массой 2000 т идет по горизонтальному участку пути с постоянной скоростью 10 м/с Коэффициент трения равен 0,05 Какую мощность развивает тепловоз на этом участке?

Answer 1

В данном случае мощность можно определить по формуле: P=F*V, где F- сила трения, которую надо преодолеть поезду, т.е работа совершается против силы трения, значится,т.к. F=μmg, m=2000000кг, g=10 м/с кв.подставляем и получаем:Р=2000000*10*0,05*10=10000000 Вт
ВСЕ!!!

Answer 2

Calculation of Power Developed by the Locomotive

To calculate the power developed by the locomotive, we can use the formula:

Power = Force × Velocity

In this case, the force acting on the locomotive is the force of friction, which can be calculated using the formula:

Force of Friction = Coefficient of Friction × Normal Force

The normal force is the force exerted by the surface on the locomotive, which is equal to the weight of the locomotive. The weight can be calculated using the formula:

Weight = Mass × Acceleration due to Gravity

Given: - Mass of the locomotive = 2000 t (tonnes) - Velocity of the locomotive = 10 m/s - Coefficient of friction = 0.05

Let's calculate the power developed by the locomotive step by step.

Step 1: Convert the mass of the locomotive from tonnes to kilograms. - 1 tonne = 1000 kg - Mass of the locomotive = 2000 t × 1000 kg/t = 2,000,000 kg

Step 2: Calculate the weight of the locomotive. - Acceleration due to gravity = 9.8 m/s^2 - Weight = Mass × Acceleration due to Gravity = 2,000,000 kg × 9.8 m/s^2 = 19,600,000 N

Step 3: Calculate the force of friction. - Coefficient of friction = 0.05 - Force of Friction = Coefficient of Friction × Normal Force = 0.05 × 19,600,000 N = 980,000 N

Step 4: Calculate the power developed by the locomotive. - Velocity of the locomotive = 10 m/s - Power = Force × Velocity = 980,000 N × 10 m/s = 9,800,000 W

Therefore, the power developed by the locomotive on this section of the track is 9,800,000 Watts.