Question

Кусок льда привязан нитью ко дну цилиндрического сосуда с водой. Над поверхностью воды находится некоторый объём льда. Нить натянута с силой Т=1 Н. На сколько и как изменится уровень воды в сосуде,.если лёд растает? Площадь сосуда S=400см2, плотность воды р=1г/см3.Помогите пожалуйста, очень очень надо, заранее спасибо =)

Answer 1

P-1г/см3
S-400см2
Изменение объема-?
м=F/g=1:10=0.1кг=100г
V=pm=100*1=100см3
Уровень воды изменится на 100 см3

Answer 2

Problem Analysis

In this problem, we have a cylindrical vessel filled with water, and a piece of ice is attached to the bottom of the vessel with a string. The ice has a certain volume above the water surface. We need to determine how the water level in the vessel will change when the ice melts.

To solve this problem, we can use the principle of buoyancy. When the ice melts, it will turn into water, which will increase the volume of water in the vessel. This increase in volume will cause the water level to rise.

Solution

To find the change in water level, we need to calculate the change in volume of the ice when it melts. We can then use this change in volume to determine the change in water level.

Let's calculate the change in volume of the ice first.

Given: - Force applied by the string, T = 1 N - Area of the vessel, S = 400 cm^2 - Density of water, p = 1 g/cm^3

The force applied by the string is equal to the weight of the ice, which is given by the formula:

T = m * g

where m is the mass of the ice and g is the acceleration due to gravity.

Since the density of water is equal to the density of ice, we can write:

m = V * p

where V is the volume of the ice.

From the given information, we can calculate the volume of the ice:

V = T / (p * g) Now, when the ice melts, it will turn into water and increase the volume of water in the vessel. The change in volume of the water is equal to the volume of the ice:

ΔV = V

To find the change in water level, we need to divide the change in volume by the area of the vessel:

Δh = ΔV / S

Substituting the value of ΔV, we get:

Δh = V / S

Now, let's calculate the change in water level.

Calculation

Using the given values: - T = 1 N - S = 400 cm^2 - p = 1 g/cm^3 - g = 9.8 m/s^2

Substituting these values into the formula for V, we get:

V = 1 / (1 * 9.8) = 0.102 cm^3

Finally, substituting the value of V into the formula for Δh, we get:

Δh = 0.102 / 400 = 0.000255 cm

Therefore, the water level in the vessel will increase by approximately 0.000255 cm when the ice melts.

Answer

The water level in the vessel will increase by approximately 0.000255 cm when the ice melts.

Note: The calculations provided are based on the given information and assumptions.