Question

Два проводника сопротивлением 5 и 10 Ом присоединены параллельно к источнику тока напряжением 20 В. Определите общее сопротивление и общую силу тока в цепи.

Answer 1

$R= \frac{R_1R_2}{R_1+R_2}$
$R= \frac{5*10}{5+10}= \frac{10}{3}$ Ом
$\mathcal I= \frac{\mathcal U}{R}$
$\mathcal I= \frac{20}{ \frac{10}{3} } = \frac{20*3}{10} =6A$

Answer 2

Сопротивление параллельных резисторов

R=R1*R2/(R1+R2)=5*10/(5+10)=50/15=3.3 Ом

Ток в цепи I=U/R=20/3.3=6.06 A

Answer 3

Calculation of Total Resistance and Total Current

To determine the total resistance and total current in the circuit, we need to consider the two resistors connected in parallel.

The formula for calculating the total resistance (Rt) of resistors connected in parallel is given by:

1/Rt = 1/R1 + 1/R2

where R1 and R2 are the resistances of the two resistors.

In this case, the resistances of the two resistors are 5 Ω and 10 Ω, respectively. Substituting these values into the formula, we get:

1/Rt = 1/5 + 1/10

Simplifying the equation:

1/Rt = 2/10 + 1/10 = 3/10

Taking the reciprocal of both sides:

Rt = 10/3 Ω

Therefore, the total resistance in the circuit is 10/3 Ω.

To calculate the total current (It) in the circuit, we can use Ohm's Law, which states that the current (I) flowing through a circuit is equal to the voltage (V) divided by the resistance (R):

I = V/R

In this case, the voltage (V) is given as 20 V and the total resistance (Rt) is 10/3 Ω. Substituting these values into the formula, we get:

It = 20 / (10/3) = 60/10 = 6 A

Therefore, the total current in the circuit is 6 A.

Conclusion

In summary, when two resistors with resistances of 5 Ω and 10 Ω are connected in parallel to a voltage source of 20 V, the total resistance in the circuit is 10/3 Ω and the total current flowing through the circuit is 6 A.