Question

T1=10с S1=50м t2=10с S2=100м a=?

Answer 1

Ответ:

а=дельтаV/дельта t

v1=0,05/0.17= 0.29 м/с

v2=0.1/0.17=0.59 м/с

а= v2-v1/t2-t1= 0.59-0.29/0.17-0.17=0 м/с2

или

v1=50/10= 5 м/с

v2=100/10=10 м/с

а= 10-5/10-10=0

В обоих случаях будет 0

Answer 2

To find acceleration ($a$), you can use the following kinematic equation:

$S = ut + \frac{1}{2}at^2$

where:

• $S$ is the displacement,
• $u$ is the initial velocity,
• $t$ is the time.

In your case, you have two sets of data (subscripts 1 and 2), and the initial velocity ($u$) is assumed to be zero since it's not given. Also, both events happen in the same time interval ($t = 10 \, \text{s}$).

For the first set of data (subscript 1):

$S_1 = ut + \frac{1}{2}a(t^2)$

Substitute $S_1 = 50 \, \text{m}$ and $t = 10 \, \text{s}$:

$50 = 0 + \frac{1}{2}a(10^2)$

$50 = 50a$

$a = 1 \, \text{m/s}^2$

For the second set of data (subscript 2):

$S_2 = ut + \frac{1}{2}a(t^2)$

Substitute $S_2 = 100 \, \text{m}$ and $t = 10 \, \text{s}$:

$100 = 0 + \frac{1}{2}a(10^2)$

$100 = 50a$

$a = 2 \, \text{m/s}^2$

So, it seems there's an inconsistency in the data provided. If the time and initial velocity are the same for both sets of data, the acceleration should be the same. Please double-check the values or provide additional information if needed.