Question

4. Найти сколько потеряет энергии только что вскипяченные 16 литров воды до температуры 25 градусов Цельсия.

Answer 1

Ответ:

Реально незнаю лвлвллвлвдвдадсдсдадададдадададад

Answer 2

Calculation of Energy Loss in Heating Water

To calculate the amount of energy lost when heating 16 liters of water to a temperature of 25 degrees Celsius, we need to consider the specific heat capacity of water and the temperature difference.

The specific heat capacity of water is approximately 4.18 Joules per gram per degree Celsius. Since we have 16 liters of water, we need to convert this volume to grams.

1 liter of water is equal to 1000 grams, so 16 liters of water is equal to 16,000 grams.

Next, we need to calculate the temperature difference. Assuming the initial temperature of the water is 100 degrees Celsius (boiling point) and we want to heat it to 25 degrees Celsius, the temperature difference is 100 - 25 = 75 degrees Celsius.

The formula to calculate the energy lost is:

Energy lost = mass of water * specific heat capacity of water * temperature difference

Let's calculate the energy loss:

Mass of water = 16,000 grams

Specific heat capacity of water = 4.18 Joules/gram/degree Celsius

Temperature difference = 75 degrees Celsius

Energy lost = 16,000 grams * 4.18 Joules/gram/degree Celsius * 75 degrees Celsius

Energy lost = 4,980,000 Joules

Therefore, when heating 16 liters of water from 100 degrees Celsius to 25 degrees Celsius, approximately 4,980,000 Joules of energy will be lost.