Question

Два одинаковых шарика находятся на расстоянии 10 см друг от друга.Они имеют одинаковые отрицательные заряды и взаимодействуют с силой 0,23мН. Найдите число "лишних"электронов вкаждом шарике

Answer 1

Дано:

e=~$-1.6 * 10^{-19}$Кл

k=~$9*10^9$

F=0.23мН=$2,3*10^{-4}$Н

q1=q2=q

x=10см=0,1м

Найти:

N(электронов)

Решение:

По закону кулона

$F=\frac{k|q_{1}||q_{2}| }{x^2} =\frac{kq^2}{x^2}$

$></p> <p>q=N*|e|</p> <p><img src=$

N=~$10^{11}$

Ответ: $10^{11}$

Answer 2

Calculation of the Number of "Extra" Electrons in Each Ball

To find the number of "extra" electrons in each ball, we can use the formula for the electric force between two charged objects:

F = k * (q1 * q2) / r^2

Where: - F is the electric force between the two objects, - k is the electrostatic constant (approximately 9 * 10^9 Nm^2/C^2), - q1 and q2 are the charges of the two objects, and - r is the distance between the centers of the two objects.

In this case, we know that the electric force between the two balls is 0.23 mN (millinewtons) and the distance between them is 10 cm (0.1 m). The charges of the two balls are the same, and we need to find the number of "extra" electrons in each ball.

Let's assume that each ball has a charge of q. Since the charges are the same, the formula becomes:

0.23 mN = (9 * 10^9 Nm^2/C^2) * (q * q) / (0.1 m)^2

Simplifying the equation:

0.23 * 10^-3 N = (9 * 10^9 Nm^2/C^2) * q^2 / (0.1)^2

0.23 * 10^-3 N = (9 * 10^9 Nm^2/C^2) * q^2 / 0.01 m^2

0.23 * 10^-3 N = (9 * 10^9 Nm^2/C^2) * q^2 / 0.01 m^2

0.23 * 10^-3 N * 0.01 m^2 = (9 * 10^9 Nm^2/C^2) * q^2

0.23 * 10^-5 Nm^2 = (9 * 10^9 Nm^2/C^2) * q^2

Dividing both sides by (9 * 10^9 Nm^2/C^2):

0.23 * 10^-5 Nm^2 / (9 * 10^9 Nm^2/C^2) = q^2

0.23 * 10^-5 / 9 * 10^9 C^2 = q^2

Taking the square root of both sides:

sqrt(0.23 * 10^-5 / 9 * 10^9 C^2) = q

Calculating the value:

q ≈ 1.61 * 10^-8 C

Since the charge of an electron is approximately -1.6 * 10^-19 C, we can calculate the number of "extra" electrons in each ball by dividing the charge q by the charge of an electron:

Number of "extra" electrons = q / (-1.6 * 10^-19 C)

Number of "extra" electrons ≈ (1.61 * 10^-8 C) / (-1.6 * 10^-19 C)

Number of "extra" electrons ≈ -1.00625 * 10^11

Therefore, each ball has approximately -1.00625 * 10^11 "extra" electrons.