Question

Сколько энергии выделится при конденсации 3кг водяного пара при температуре 100•С?

Answer 1

Ответ:

по формуле количества теплоты q=r*m  q=-2,3*10*6*3=10*6 дж выделится 6,9 мдж ответ-6,9мдж

Объяснение:

Answer 2

Calculation of Energy Released during Condensation of Water Vapor

To calculate the energy released during the condensation of 3 kg of water vapor at a temperature of 100°C, we can use the formula:

Q = m * L

Where: - Q is the energy released (in joules) - m is the mass of the water vapor (in kilograms) - L is the latent heat of vaporization of water (in joules per kilogram)

The latent heat of vaporization of water is the amount of energy required to change 1 kilogram of water from a liquid to a vapor state at a given temperature. For water at 100°C, the latent heat of vaporization is approximately 2,260,000 joules per kilogram.

Substituting the values into the formula, we have:

Q = 3 kg * 2,260,000 J/kg

Calculating the value, we get:

Q = 6,780,000 joules

Therefore, approximately 6,780,000 joules of energy will be released during the condensation of 3 kg of water vapor at a temperature of 100°C.

Please note that this calculation assumes ideal conditions and does not take into account any losses or inefficiencies that may occur in the process.

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