Question

Средняя кинетическая энергия поступательного движения молекулы идеального газа равна 6⋅10–21 Дж, давление газа ─ 4 мПа. Найти число молекул в единице объема.

Answer 1

Ответ:

Из формулы основного уравнения МКТ

р=(2 / 3)*Ек*n. ( p -давление=4*10^(-3)Па, n -концентрация, Ек - средняя кинетическая энергия) выразим концентрацию

n=3p / 2Ек.

n=3*4*10^(-3) / 2*6,4*10^(-21)=0,94*10^18. ( 1/куб. м)

Answer 2

Calculation of the Number of Molecules in a Unit Volume of an Ideal Gas

To find the number of molecules in a unit volume of an ideal gas, we can use the ideal gas law and the given information about the average kinetic energy and pressure of the gas.

The ideal gas law states that:

PV = nRT

Where: - P is the pressure of the gas - V is the volume of the gas - n is the number of moles of the gas - R is the ideal gas constant - T is the temperature of the gas

We can rearrange the equation to solve for the number of moles:

n = PV / RT

Since we are interested in the number of molecules in a unit volume, we can assume a volume of 1 m^3. Therefore, V = 1 m^3.

The given pressure is -4 mPa. However, pressure cannot be negative, so we will consider the absolute value of the pressure, which is 4 mPa.

The ideal gas constant, R, is a constant value equal to 8.314 J/(mol·K).

The average kinetic energy of the molecules is given as 6 × 10^(-21) J.

Now we can substitute the values into the equation to find the number of moles:

n = (4 × 10^(-3) Pa) × (1 m^3) / (8.314 J/(mol·K) × T)

To find the temperature, we need additional information. Please provide the temperature of the gas in order to complete the calculation.