Question

Обчислити масу і об'єм 6 · 1022 молекул кисню при нормальних умовах.

Answer 1

Ответ:

n(O2)= N/Na

n(O2)=6*10^22 молекул/6*10*23 молекул/моль=0,1 моль

m (O2)=M*n

m(O2)=32г/моль*0,1 моль=3,2 г

V(O2)= Vm * n

V(o2)= 22.4 л/моль* 0,1 моль=2,24 л

Answer 2

Calculation of Mass and Volume of Oxygen Molecules

To calculate the mass and volume of 6 × 10^22 oxygen molecules at normal conditions, we need to consider the molar mass of oxygen and Avogadro's number.

1. Molar Mass of Oxygen: The molar mass of oxygen (O2) is approximately 32 g/mol.

2. Avogadro's Number: Avogadro's number (NA) is approximately 6.022 × 10^23 mol^-1.

Now, let's calculate the mass and volume of 6 × 10^22 oxygen molecules.

Calculation of Mass:

The mass of 6 × 10^22 oxygen molecules can be calculated using the following formula:

Mass = Number of Molecules × Molar Mass

Substituting the values: Mass = 6 × 10^22 molecules × (32 g/mol) Mass = 1.92 × 10^24 g

Therefore, the mass of 6 × 10^22 oxygen molecules is approximately 1.92 × 10^24 grams.

Calculation of Volume:

To calculate the volume of 6 × 10^22 oxygen molecules, we need to consider the ideal gas law, which states:

PV = nRT

Where: P = Pressure (at normal conditions, it is approximately 1 atm) V = Volume n = Number of moles R = Ideal gas constant (approximately 0.0821 L·atm/(mol·K)) T = Temperature (at normal conditions, it is approximately 273 K)

Rearranging the formula to solve for volume (V): V = (nRT) / P

Substituting the values: V = (6 × 10^22 molecules / (6.022 × 10^23 molecules/mol)) × (0.0821 L·atm/(mol·K)) × 273 K / 1 atm V = 0.091 L

Therefore, the volume of 6 × 10^22 oxygen molecules at normal conditions is approximately 0.091 liters.

Please note that these calculations assume ideal gas behavior and normal conditions.