Question

1. (1 балл) Боевой снаряд, летящий со скоростью 12 м/с, разорвался на два осколка массами Зи 12 кг. Скорость большего осколка возросла до 18 м/с по направлению движения. Определите скорость и направление движения меньшего осколка.​

Answer 1

Ответ: 12м/с

Объяснение:

Дано:

V=12м/с

m1=3кг

m2=12кг

V2=18м/с

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V1-?

По закону сохранения импульсов:

V*(m1+m2)=m1*V1+m2*V2

Отсюда V1=(m2*V2-V(m1+m2))/m1=(12*18-12*(12+3))/3=12м/с

Answer 2

Calculation of the Speed and Direction of the Smaller Fragment

To determine the speed and direction of the smaller fragment, we can use the principle of conservation of momentum. According to this principle, the total momentum before the explosion is equal to the total momentum after the explosion.

Let's denote the mass of the larger fragment as m1 and its velocity as v1, and the mass of the smaller fragment as m2 and its velocity as v2.

Before the explosion: - Mass of the larger fragment (m1) = 12 kg - Velocity of the larger fragment (v1) = 12 m/s

After the explosion: - Mass of the larger fragment remains the same (m1 = 12 kg) - Velocity of the larger fragment increases to 18 m/s in the direction of motion

To find the velocity and direction of the smaller fragment, we need to solve the momentum conservation equation:

m1 * v1 = m1 * v1 + m2 * v2

Substituting the given values:

12 kg * 12 m/s = 12 kg * 18 m/s + m2 * v2

Simplifying the equation:

144 kg·m/s = 216 kg·m/s + m2 * v2

Rearranging the equation:

m2 * v2 = 144 kg·m/s - 216 kg·m/s

m2 * v2 = -72 kg·m/s

Since the mass of the smaller fragment (m2) is positive, the velocity (v2) must be negative to satisfy the equation.

Therefore, the speed of the smaller fragment is 72 m/s in the opposite direction of the larger fragment's motion.

Answer: The speed of the smaller fragment is 72 m/s in the opposite direction of the larger fragment's motion.