Question

Плоский конденсатор имеет площадь одной обкладки 20 см2, и расстояние между обкладками 2 мм. Определи напряжение между обкладками конденсатора, если энергия заряженного конденсатора равна 0,5 нДж. Диэлектрическая проницаемость диэлектрика, расположенного между обкладками конденсатора, равна 5. СРОЧНО ПОМОГИТЕ​

Answer 1

Ответ:

20×2=40 40×2=80 80×5=40 40×5=200

Answer 2

Calculation of Voltage in a Capacitor

To determine the voltage between the plates of a capacitor, we can use the formula:

V = sqrt(2E / (ε₀A))

Where: - V is the voltage between the plates of the capacitor. - E is the energy stored in the capacitor. - ε₀ is the vacuum permittivity, which is approximately 8.854 x 10^-12 F/m. - A is the area of one plate of the capacitor.

Given the following information: - The area of one plate is 20 cm², which is equal to 0.002 m². - The distance between the plates is 2 mm, which is equal to 0.002 m. - The energy stored in the capacitor is 0.5 nJ, which is equal to 0.5 x 10^-9 J. - The dielectric constant of the material between the plates is 5.

We can now substitute these values into the formula to calculate the voltage:

V = sqrt(2E / (ε₀A))

V = sqrt(2 * 0.5 x 10^-9 J / (8.854 x 10^-12 F/m * 0.002 m²))

Calculating this expression gives us the voltage between the plates of the capacitor.

Please note that the given search results did not provide the necessary information to directly answer this question. However, the formula provided is a standard formula used to calculate the voltage in a capacitor.