Question

Я На столе стоит пустая пластиковая коробка без крышки, ширина а = 10 см, длина коробки b = 20 см, а высота с = 8 см, толщина стенок и днa d = 1 см. Плотность пластика р = 1800 кг/м3. Какое давление р коробка оказывает на стол? Ускорение свободного падения равно g = 10 Н/кг. ​

Answer 1

Ответ:

533

Объяснение:

Answer 2

Ответ:

533

Объяснение:

проверенно

Answer 3

Calculation of Pressure Exerted by the Box on the Table

To calculate the pressure exerted by the box on the table, we need to determine the weight of the box and the area over which the weight is distributed.

The weight of the box can be calculated using the formula:

Weight = Volume x Density x Acceleration due to gravity

The volume of the box can be calculated using the formula:

Volume = Length x Width x Height

Given the following dimensions: - Width (a) = 10 cm - Length (b) = 20 cm - Height (c) = 8 cm - Thickness of walls and base (d) = 1 cm - Density of plastic (ρ) = 1800 kg/m³ - Acceleration due to gravity (g) = 10 N/kg

Let's calculate the weight of the box first:

Volume = 20 cm x 10 cm x 8 cm = 1600 cm³ = 0.0016 m³ Weight = 0.0016 m³ x 1800 kg/m³ x 10 N/kg = 28.8 N

Now, let's calculate the area over which the weight is distributed. Since the box is rectangular, the area is equal to the product of the length and width of the base:

Area = Length x Width = 20 cm x 10 cm = 200 cm² = 0.02 m²

Finally, we can calculate the pressure exerted by the box on the table using the formula:

Pressure = Weight / Area

Pressure = 28.8 N / 0.02 m² = 1440 N/m²

Therefore, the box exerts a pressure of 1440 N/m² (or 1440 Pa) on the table.

Please note that this calculation assumes the weight of the box is evenly distributed over the entire base area and does not take into account any additional factors such as friction or uneven weight distribution.

Let me know if there's anything else I can help you with!