Question

Під час кипіння 10 кг води перетворилися на пару. Знайти Q​

Answer 1

Ответ:

4200 :10 = 420

Объяснение:

4200- вода

Answer 2

Calculation of Q during the boiling of 10 kg of water

To find the value of Q during the boiling of 10 kg of water, we need to use the equation:

Q = m * ΔHvap

Where: - Q is the heat energy absorbed or released during the phase change (in joules) - m is the mass of the substance undergoing the phase change (in kilograms) - ΔHvap is the heat of vaporization, which is the amount of heat energy required to convert one unit of mass from a liquid to a gas at a constant temperature (in joules per kilogram)

In this case, we are given that 10 kg of water is converted into steam (vapor). We need to find the value of Q.

The heat of vaporization for water is approximately 2.26 × 10^6 J/kg.

Using the equation, we can calculate Q as follows:

Q = 10 kg * 2.26 × 10^6 J/kg

Calculating the value, we get:

Q = 2.26 × 10^7 J

Therefore, during the boiling of 10 kg of water, the heat energy absorbed or released (Q) is approximately 2.26 × 10^7 joules.

I hope this helps! Let me know if you have any further questions.

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