Question

Срочнооооооо!!!!!! В некоторой исследовательской установке электроны разгоняются прохождением через разность потенциалов 1000 В, а затем отклоняются магнитным полем. При этом входя в поле, электрон описывает в нем окружность радиусом 20 см. Определите величину напряженности магнитного поля. Масса электрона равна 9,1⋅10−31 кг, заряд электрона −1,6⋅10−19 Кл

Answer 1

Ответ:

5,33 * 10^(-4) Тл

Объяснение:

из полученного уравнения, просто выражаем В и получаем ответ 5,33 * 10^(-4) Тл

Answer 2

Calculation of the Magnetic Field Strength

To determine the magnetic field strength, we can use the formula for the centripetal force experienced by the electron:

F = (m * v^2) / r

Where: - F is the centripetal force - m is the mass of the electron (9.1⋅10^(-31) kg) - v is the velocity of the electron - r is the radius of the circular path (20 cm)

The centripetal force is provided by the magnetic force acting on the electron:

F = q * v * B

Where: - q is the charge of the electron (-1.6⋅10^(-19) C) - v is the velocity of the electron - B is the magnetic field strength

By equating the two expressions for the force, we can solve for B:

(m * v^2) / r = q * v * B

Simplifying the equation, we find:

B = (m * v) / (q * r)

Now, let's calculate the magnetic field strength using the given values.

Given: - Potential difference: 1000 V - Radius of the circular path: 20 cm - Mass of the electron: 9.1⋅10^(-31) kg - Charge of the electron: -1.6⋅10^(-19) C

To find the velocity of the electron, we can use the formula for the kinetic energy:

K.E. = q * V

Where: - K.E. is the kinetic energy - q is the charge of the electron - V is the potential difference

Rearranging the equation, we find:

V = K.E. / q

Substituting the given values, we have:

V = (9.1⋅10^(-31) kg * v^2) / (20 cm)

Simplifying the equation, we find:

v^2 = (20 cm * V) / (9.1⋅10^(-31) kg)

Now, let's calculate the velocity of the electron:

v = sqrt((20 cm * V) / (9.1⋅10^(-31) kg))

Substituting the given potential difference of 1000 V, we have:

v = sqrt((20 cm * 1000 V) / (9.1⋅10^(-31) kg))

Calculating the value of v, we find:

v ≈ 6.32 x 10^6 m/s

Now, let's substitute the values of m, v, q, and r into the equation for B:

B = (9.1⋅10^(-31) kg * 6.32 x 10^6 m/s) / (-1.6⋅10^(-19) C * 0.2 m)

Calculating the value of B, we find:

B ≈ -0.071 T

Therefore, the magnitude of the magnetic field strength is approximately 0.071 T.

Note: The negative sign indicates that the magnetic field is directed opposite to the direction of the electron's motion.