Question

Срочно 1. картофелина массой 65 г имеет объём 48 см³. определите плотность картофеля. Ответ выразите в единицах СИ2. ОБъём чугунного ядра корабельной пушки 5000 см³. Определите массу ядра, если плотность чугуна 7 г/см³3. Дубровый брусок имеет массу 850 г и плотность 700 кг/м³. определите его объем. ​

Answer 1

Ответ: 1650кг/м³; 35кг; 1214см³

Объяснение:

Дано:

m=65г

V=48см³

==========

ρ-?

ρ=m/V=65/48=1,35г/см³=1650кг/м³

Дано:

V=5000cм³

ρ=7г/см³

==========

m-?

m=ρ*V=7*5000=35000г=35кг

Дано:

m=850г

ρ=700кг/м³=0,7г/см³

==============

V-?

V=m/ρ=850/0,7=1214см³

Answer 2

1. To determine the density of the potato, we can use the formula:

Density = Mass / Volume

Given that the mass of the potato is 65 g and the volume is 48 cm³, we can substitute these values into the formula:

Density = 65 g / 48 cm³

To express the density in SI units, we need to convert the volume from cm³ to m³ and the mass from grams to kilograms:

Density = 65 g / (48 cm³ * (1 m / 100 cm)³) = 65 g / 0.000048 m³ = 1,354,166.67 kg/m³

Therefore, the density of the potato is approximately 1,354,166.67 kg/m³. [[1]]

2. To determine the mass of the iron core of the ship cannon, we can use the formula:

Mass = Density * Volume

Given that the volume of the iron core is 5000 cm³ and the density of iron is 7 g/cm³, we can substitute these values into the formula:

Mass = 7 g/cm³ * 5000 cm³ = 35,000 g

To express the mass in SI units, we need to convert grams to kilograms:

Mass = 35,000 g * (1 kg / 1000 g) = 35 kg

Therefore, the mass of the iron core of the ship cannon is 35 kg. [[2]]

3. To determine the volume of the oak block, we can use the formula:

Volume = Mass / Density

Given that the mass of the oak block is 850 g and the density is 700 kg/m³, we can substitute these values into the formula:

Volume = 850 g / (700 kg/m³) = 0.001214 m³

Therefore, the volume of the oak block is approximately 0.001214 m³. [[3]]