Question

Помогите пожалуйста. В тепловой машине за счёт каждого килоджоуля энергии, получаемой от нагревателя, совершается работа 300 Дж. Определите КПД машины.

Answer 1

Ответ:

КПД - отношение полезной работы к затраченной.

T.e n=100%*Ап/Аз

n=100*300/1000=30%

Answer 2

Calculation of Efficiency (КПД) in a Heat Engine

To determine the efficiency (КПД) of a heat engine, we need to know the amount of work done (работа) and the energy input from the heater (нагреватель). In this case, we are given that the work done is 300 J (Дж) for every kilojoule (килоджоуль) of energy input.

The efficiency (КПД) of a heat engine is defined as the ratio of the work done by the engine to the energy input from the heater. Mathematically, it can be expressed as:

КПД = (работа / энергия входа) * 100%

Substituting the given values into the equation, we have:

КПД = (300 J / 1 kJ) * 100%

Simplifying the expression, we find:

КПД = 30%

Therefore, the efficiency (КПД) of the heat engine is 30%.

Please note that the provided search results did not contain relevant information for this specific calculation. However, the calculation is based on the fundamental definition of efficiency in a heat engine.