Question

Амплитуда колебаний точки струны 3мм частота 0.5кГц. Какой путь пройдёт точка за 0.2с​

Answer 1

Дано:

a = 3 мм = 0,003 м

f = 0,5 кГц = 500 Гц

t = 0,2 с

Найти:

S - ?

Формула:

S= 4an; n=ft

Решение:

S = 4 × 0,003 × 500 = 6 м

Ответ: за 2 сек. => 8 м пройдёт

Answer 2

Calculation of the Displacement of the Point on the String

The displacement of a point on a string undergoing simple harmonic motion can be calculated using the formula:

Displacement (x) = Amplitude * sin(2πft)

Where: - Amplitude (A) is the maximum displacement from the equilibrium position, given as 3 mm in this case. - f is the frequency of the oscillation, given as 0.5 kHz. - t is the time, given as 0.2 s.

Calculation

Using the given values: - Amplitude (A) = 3 mm = 0.003 m - Frequency (f) = 0.5 kHz = 500 Hz - Time (t) = 0.2 s

We can calculate the displacement of the point on the string using the formula:

Displacement (x) = 0.003 * sin(2π * 500 * 0.2)

Result

Calculating the value: Displacement (x) ≈ 0.003 * sin(628.32) ≈ 0.003 * 0.951 ≈ 0.002853 m

Therefore, the point on the string will move approximately 0.002853 meters in 0.2 seconds.