Question

Ведро с водой массой 8 кг подняли из колодца глубиной 10 м равноускоренно за 3,6 с. Определите величину совершённой при этом работу.

Answer 1

Ответ:

Объяснение:

Дано:

m = 8 кг

H = 10 м

t = 3,6 с

_________

A - ?

1)

Найдем ускорение ведра:

H = a·t² / 2

a = 2·H / t² = 2·10 / 3,6² ≈ 1,54 м/с²

2)

Вес ведра, движущегося вверх с ускорением:

P = m·(g + a) = 8·(9,8 + 1,54) ≈ 90,7 H

3)

Работа:

A = P·H = 90,7·10 ≈ 910 Дж

Answer 2

Calculation of Work Done

To calculate the work done in lifting the bucket of water, we can use the formula:

Work (W) = Force (F) × Distance (d)

In this case, the force is the weight of the bucket of water, and the distance is the depth of the well.

Given: - Mass (m) = 8 kg - Depth (h) = 10 m - Time (t) = 3.6 s

First, let's calculate the force (F) exerted to lift the bucket of water: F = m × g, where g is the acceleration due to gravity (approximately 9.81 m/s^2).

Then, we can calculate the work done using the formula mentioned above.

Calculation Steps

1. Calculate the force (F): - F = m × g - F = 8 kg × 9.81 m/s^2 - F ≈ 78.48 N

2. Calculate the work done (W): - W = F × d - W = 78.48 N × 10 m - W = 784.8 J

So, the work done in lifting the bucket of water from a depth of 10 m in 3.6 s is approximately 784.8 joules.

The calculation is based on the formula for work and the given values of mass, depth, and time.