Question

Пружина имеет коэффициент жёсткости 20н/м определите на сколько оразтянится Пружина при усилии 6.4 н

Answer 1

Ответ:

32 см

Объяснение:

k=20Н/м

F=6,4 Н

x=?

F=kx

x=F/k

х=6,4/20=0,32 м=32 см

Answer 2

Calculating Spring Extension

To calculate the extension of a spring, we can use Hooke's Law, which states that the force exerted by a spring is directly proportional to the extension of the spring. The formula for Hooke's Law is:

F = kx

Where: - F is the force applied to the spring (in newtons, N) - k is the spring constant or coefficient of stiffness (in newtons per meter, N/m) - x is the extension or compression of the spring from its equilibrium position (in meters, m)

Applying the Formula

Given: - k (spring constant) = 20 N/m - F (applied force) = 6.4 N

We can rearrange the formula to solve for x:

x = F / k

Substitute the given values:

x = 6.4 N / 20 N/m

Calculating the Extension

Now, let's calculate the extension:

x = 6.4 N / 20 N/m = 0.32 m

So, the spring will extend by 0.32 meters when a force of 6.4 N is applied.

This calculation is based on Hooke's Law and the given values of the spring constant and the applied force.