Question

Резистор сопротивлением 6 Ом соединен последовательно с железной проволокой сечением 0,25 мм2 и длиной 60 см. Определите силу тока в цепи при подаче на нее напряжения 24 В.

Answer 1

Ответ:

Сила тока в цепи 3.85 Ампер

Объяснение:

Дано:

Посл. соединение

R1$I = \frac{U}{R_{1}+R_{2} }$= 6 Ом

S = 0.25 мм2 = 0.25 * 10^-6 м2

l = 60 см = 0.6 м

ρ = 0.1 Ом*мм2/м

U = 24 В

Найти: I

Решение: Так как соединение последоательное, то сила тока I1 = I2 = I,  U = U1 + U2, а R = R1 + R2. Тогда по закону Ома I = U/R, или $I = \frac{U}{R_{1}+R_{2} }$ . Найдём R2. Тогда по формуле получим: R2 = ρ * $\frac{l}{S}$ = 0.1 Ом*мм2/м * (0.6 м / 0.25 * мм2) = 0.24 Ом. Подставляем в итоговую формулу и получаем I = 24 В / 6.24 Ом = 3.85 А

Answer 2

Calculating Current in the Circuit

To determine the current in the circuit, we can use Ohm's law, which states that the current flowing through a conductor between two points is directly proportional to the voltage across the two points and inversely proportional to the resistance between them. The formula for Ohm's law is:

I = V / R

Where: - I = current in the circuit (in amperes, A) - V = voltage applied to the circuit (in volts, V) - R = total resistance in the circuit (in ohms, Ω)

Given: - Resistance of the resistor, R1 = 6 Ω - Length of the iron wire, L = 60 cm = 0.6 m - Cross-sectional area of the iron wire, A = 0.25 mm² = 0.25 × 10^-6 m² - Voltage applied to the circuit, V = 24 V

First, we need to calculate the resistance of the iron wire using the formula:

R2 = (ρ * L) / A

Where: - R2 = resistance of the iron wire - ρ = resistivity of the material - L = length of the wire - A = cross-sectional area of the wire

Then, we can calculate the total resistance in the circuit, R_total, by adding the resistances of the resistor and the iron wire in series:

R_total = R1 + R2

Finally, we can use Ohm's law to find the current in the circuit:

I = V / R_total

Let's calculate the resistance of the iron wire, the total resistance in the circuit, and the current flowing through the circuit.

Calculations

Using the provided data and the formula for the resistance of the iron wire, we can calculate the resistance of the iron wire, the total resistance in the circuit, and the current flowing through the circuit.

1. Calculate the Resistance of the Iron Wire (R2) - Resistivity of iron, ρ = 9.71 × 10^-8 Ω·m - Length of the iron wire, L = 0.6 m - Cross-sectional area of the iron wire, A = 0.25 × 10^-6 m²

R2 = (ρ * L) / A

R2 = (9.71 × 10^-8 * 0.6) / (0.25 × 10^-6) R2 ≈ 0.2324 Ω

2. Calculate the Total Resistance in the Circuit (R_total) - Resistance of the resistor, R1 = 6 Ω - Resistance of the iron wire, R2 ≈ 0.2324 Ω

R_total = R1 + R2 R_total ≈ 6.2324 Ω

3. Calculate the Current in the Circuit (I) - Voltage applied to the circuit, V = 24 V - Total resistance in the circuit, R_total ≈ 6.2324 Ω

I = V / R_total I ≈ 24 / 6.2324 I ≈ 3.85 A

Answer

The current flowing through the circuit when a voltage of 24 V is applied is approximately 3.85 A.