Question

Помогите решить!!! 1. Автомобиль тормозит с ускорением 20 м/с2 . Найдите коэффициент трения скольжения, если масса автомобиля равна 2т. 2. Две пружинки разной длины скреплены концами, где в ходе эксперимента равномерно растягивают. Пружинка женскостью 100 Н/м удлинилась на 10 см. Какова жёсткость 2 пружинки, если ее удлинение равно 2 см?

Answer 1

Ответ:
2*20=40
N=40*0,75
F =30
30/2*20=30/40=0.75
Объяснение:
/-Дробь а риска дробу ровно знаку деланию
0.75- коэффициент резины по бетону

Answer 2

Problem 1: Finding the Coefficient of Sliding Friction

To find the coefficient of sliding friction, we need to use the equation of motion for the car. The equation is:

F_net = m * a

where: - F_net is the net force acting on the car, - m is the mass of the car, and - a is the acceleration of the car.

In this case, the net force acting on the car is the force of friction, which can be calculated using the equation:

F_friction = μ * m * g

where: - F_friction is the force of friction, - μ is the coefficient of sliding friction, - m is the mass of the car, and - g is the acceleration due to gravity (approximately 9.8 m/s^2).

Given that the acceleration of the car is 20 m/s^2 and the mass of the car is 2 tons (or 2000 kg), we can substitute these values into the equation to solve for the coefficient of sliding friction:

F_friction = μ * m * g μ * m * g = m * a μ * g = a μ = a / g

Substituting the given values, we get:

μ = 20 m/s^2 / 9.8 m/s^2

Calculating this, we find:

μ ≈ 2.04

Therefore, the coefficient of sliding friction is approximately 2.04.