Question

ЕРС джерела струму 6 В, а внутрішній опір 0.8 Ом. Знайти покази приладів, якщо R1 = 2 Ом, R2 = 3 Ом. Знайти потужність на резисторі R2 і кількість теплоти, яка виділяється на резисторі R1 протягом 2 хвилин. Можно ответ этой задачи? Срочно нужно

Answer 1

Ответ:

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Answer 2

Calculation of Current and Voltage

To solve this problem, we need to use Ohm's law, which states that the current flowing through a conductor is equal to the voltage across the conductor divided by its resistance.

Given: - Voltage (V) = 6 V - Internal resistance (r) = 0.8 Ω - Resistance of R1 (R1) = 2 Ω - Resistance of R2 (R2) = 3 Ω

To find the current (I) flowing through the circuit, we can use the formula:

I = V / (r + R1 + R2)

Substituting the given values, we get:

I = 6 V / (0.8 Ω + 2 Ω + 3 Ω)

Now, let's calculate the current.

Calculation of Current:

Using the formula above, we can calculate the current flowing through the circuit:

I = 6 V / (0.8 Ω + 2 Ω + 3 Ω) = 6 V / 5.8 Ω ≈ 1.034 A

Therefore, the current flowing through the circuit is approximately 1.034 A.

Calculation of Voltages across R1 and R2:

To find the voltage across each resistor, we can use Ohm's law again. The voltage across a resistor is equal to the current flowing through it multiplied by its resistance.

Voltage across R1 (V1) = I * R1

Voltage across R2 (V2) = I * R2

Substituting the values, we get:

V1 = 1.034 A * 2 Ω ≈ 2.068 V

V2 = 1.034 A * 3 Ω ≈ 3.102 V

Therefore, the voltage across R1 is approximately 2.068 V, and the voltage across R2 is approximately 3.102 V.

Calculation of Power on R2:

The power (P) on a resistor can be calculated using the formula:

P = (I^2) * R

Substituting the values, we get:

P2 = (1.034 A)^2 * 3 Ω ≈ 3.155 W

Therefore, the power on resistor R2 is approximately 3.155 W.

Calculation of Heat on R1:

To calculate the amount of heat (Q) generated on a resistor, we can use the formula:

Q = P * t

Given that the time (t) is 2 minutes (or 120 seconds), we can calculate the heat on R1:

Q1 = P1 * t = (1.034 A)^2 * 2 Ω * 120 s ≈ 0.496 J

Therefore, the amount of heat generated on resistor R1 over 2 minutes is approximately 0.496 J.

Please note that the calculations provided are based on the given values and assumptions.