Question

Генератор має ЕРС 500 В і внутрішній опір 4 Ом, до нього приєднали нагрівач із опором 21 Ом. Визначити силу струму, спад напруги і струм короткого замикання.

Answer 1

Ответ: 20А; 80В; 125А

Объяснение:

Дано:

Е=500В

r=4 Ом

R=21 Ом

---------------

I-?; Uген-?; Iкз-?

I=Е/(R+r)=500/(4+21)=20А

Uген=r*I=4*20=80В

Iкз=Е/r=500/4=125А

Answer 2

Calculating Current, Voltage Drop, and Short Circuit Current

To calculate the current, voltage drop, and short circuit current in the given scenario, we can use the following formulas:

1. Current (I) = Voltage (V) / Resistance (R) 2. Voltage Drop (Vd) = Current (I) * Resistance (R) 3. Short Circuit Current (Isc) = Voltage (V) / Total Resistance

Given values: - Voltage (V) = 500 V - Internal Resistance (R_internal) = 4 Ω - Heater Resistance (R_heater) = 21 Ω

Calculating Current

Using the formula Current (I) = Voltage (V) / Resistance (R), we can calculate the current flowing through the circuit: - Current (I) = 500 V / (4 Ω + 21 Ω) - Current (I) = 500 V / 25 Ω - Current (I) ≈ 20 A

Calculating Voltage Drop

Using the formula Voltage Drop (Vd) = Current (I) * Resistance (R), we can calculate the voltage drop across the heater: - Voltage Drop (Vd) = 20 A * 21 Ω - Voltage Drop (Vd) ≈ 420 V

Calculating Short Circuit Current

Using the formula Short Circuit Current (Isc) = Voltage (V) / Total Resistance, we can calculate the short circuit current: - Short Circuit Current (Isc) = 500 V / 4 Ω - Short Circuit Current (Isc) ≈ 125 A

Therefore, in the given scenario: - The current flowing through the circuit is approximately 20 A. - The voltage drop across the heater is approximately 420 V. - The short circuit current is approximately 125 A.