Question

балон містить стиснений газ під тиском 500кПа. яким стане тиск газу якщо з балона витече половина маси газу а температура підвищиться від 17

Answer 1

Дано:p1=500 кПа

m1=1/2 m1

T1=17 °C=290К

T2=27 °C=300 К

Найти:p2=?

Решение:P=(m/v)*R*T

P2/P1=(1/2*m)/м)*(м/m1)*(R/R1)*(T2/T1)

(P2/P1)=(1/2)*(T2/T1)

P2/(500*10^3)=(1/2)*(300/290)≈258620

Ответ:P2≈258621 Па

Answer 2

When half of the gas mass leaks out of the container and the temperature increases from 17°C, we can calculate the new pressure using the ideal gas law. The ideal gas law states that the pressure of a gas is directly proportional to its temperature and the number of gas molecules, and inversely proportional to the volume of the container.

The ideal gas law equation is:

PV = nRT

Where: - P is the pressure of the gas - V is the volume of the container - n is the number of gas molecules (moles) - R is the ideal gas constant - T is the temperature of the gas in Kelvin

To solve for the new pressure, we need to know the initial pressure, the initial mass of the gas, and the volume of the container. Unfortunately, the initial pressure and volume are not provided in the question. Therefore, it is not possible to calculate the new pressure without this information.

If you have the initial pressure and volume, please provide them so that I can help you calculate the new pressure.