Question

Координата тела массой 6 кг изменяется при прямолинейном движении законом х=-5t+t²(значение величин в формуле приведено в СI). Определите модуль равнодействующей всех приложенных к телу сил.

Answer 1

Ответ:

F=12H

Объяснение:

1) Половина ускорения a/2 - это коэффициент перед t² в уравнении движения. Следовательно, а=2*1=2м/с²

2) Модуль равнодествующих сил:

F=m*a=6*2=12H

Answer 2

Calculation of the Resultant Force on a Body

To determine the magnitude of the resultant force acting on a body with a mass of 6 kg, we need to analyze the equation of motion provided: x = -5t + t².

The equation represents the displacement of the body as a function of time. To find the resultant force, we need to differentiate the equation twice with respect to time to obtain the acceleration. The force acting on the body is given by Newton's second law: F = ma, where F is the force, m is the mass, and a is the acceleration.

Let's calculate the acceleration by differentiating the equation twice:

1. First differentiation: - Differentiating x = -5t + t² with respect to time (t), we get v = dx/dt. - The velocity (v) of the body is given by v = -5 + 2t.

2. Second differentiation: - Differentiating v = -5 + 2t with respect to time (t), we get a = dv/dt. - The acceleration (a) of the body is given by a = 2.

Now that we have the acceleration, we can calculate the resultant force using Newton's second law:

F = ma = 6 kg * 2 m/s² = 12 N.

Therefore, the magnitude of the resultant force acting on the body is 12 N.

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