Question

Електровоз під час рушання місця залізничного состава розвиває максимальну силу тяги в50 кн. Якого прискорення він надасть составу масою 3250 т, якщо коефіцієнт опору дорівнює 0,005? ​

Answer 1

Объяснение:

тільки замість 650 кН, ми підкладаємо 50кН=5*10⁵Н, а в розв'язку 5*10⁵Н : 3,25*10⁶кг - 0,005*10 м/с²=1,5*10¹¹ м/с²

Answer 2

To calculate the acceleration provided by the electric locomotive to the train, we can use Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration. In this case, the force is the maximum traction force of 50 kN, and the mass of the train is 3250 tons.

Calculation:

1. Convert the force from kilonewtons (kN) to newtons (N): - 1 kN = 1000 N - Therefore, the maximum traction force is 50 kN * 1000 N/kN = 50,000 N.

2. Convert the mass of the train from tons to kilograms: - 1 ton = 1000 kilograms (kg) - Therefore, the mass of the train is 3250 tons * 1000 kg/ton = 3,250,000 kg.

3. Calculate the acceleration using Newton's second law of motion: - Force = mass * acceleration - Rearranging the equation, acceleration = force / mass - acceleration = 50,000 N / 3,250,000 kg = 0.0154 m/s^2.

Therefore, the electric locomotive will provide an acceleration of 0.0154 m/s^2 to the train with a mass of 3250 tons, assuming a coefficient of resistance of 0.005.