Question

сила пружності яка виникае у пружині при її видовженні на 10 см дорівнює 20 H. Яка жорсткість пружини?

Answer 1

Дано:

x=10 см=0,1 м

Fпруж=20 Н

k-?

Розв'язання:

Fпруж=kx => k=Fпруж/x

k=20/0,1=200 Н/м

Відповідь:Жорсткість пружини 200 Н/м.

Answer 2

Calculating the Spring Constant

The spring constant, denoted by k, represents the stiffness of a spring and is a measure of how much force is needed to stretch or compress a spring by a certain distance. The formula to calculate the spring constant is:

k = F / x

Where: - k = spring constant - F = force applied to the spring - x = displacement of the spring from its equilibrium position

In this case, the force applied to the spring is 20 H (H is the symbol for the unit of force, which is the hectonewton), and the displacement of the spring is 10 cm (which is 0.1 m). Therefore, using the formula:

k = 20 H / 0.1 m = 200 H/m

So, the spring constant of the given spring is 200 H/m.

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Conclusion

The spring constant of the given spring, when it is stretched by 10 cm, is 200 H/m.