Question

Тролейбус масою 20 т рухається з прискоренням 1,5 м/с Сила тяги тролейбуса дорівнює 50KH. знайти коефіцієнт тертя коліс об дорогу ​​

Answer 1

відповідь:

0,1

пояснення:

по суті нічого нового я не написав)

Answer 2

Calculation of the Coefficient of Friction

To find the coefficient of friction between the wheels of the trolleybus and the road, we can use the equation:

Force of friction = Mass of the trolleybus × Acceleration

Given that the mass of the trolleybus is 20 t (where 1 t = 1000 kg) and the acceleration is 1.5 m/s², we can calculate the force of friction:

Force of friction = (20 t) × (1.5 m/s²)

Converting the mass to kilograms:

Force of friction = (20,000 kg) × (1.5 m/s²)

Calculating the force of friction:

Force of friction = 30,000 N

Now, we can use the equation for the force of friction:

Force of friction = Coefficient of friction × Normal force

The normal force is equal to the weight of the trolleybus, which can be calculated using the equation:

Weight = Mass × Gravity

Given that the mass of the trolleybus is 20 t and the acceleration due to gravity is approximately 9.8 m/s², we can calculate the weight:

Weight = (20 t) × (9.8 m/s²)

Converting the mass to kilograms:

Weight = (20,000 kg) × (9.8 m/s²)

Calculating the weight:

Weight = 196,000 N

Now, we can substitute the values into the equation for the force of friction:

30,000 N = Coefficient of friction × 196,000 N

Simplifying the equation:

Coefficient of friction = 30,000 N / 196,000 N

Calculating the coefficient of friction:

Coefficient of friction ≈ 0.153

Therefore, the coefficient of friction between the wheels of the trolleybus and the road is approximately 0.153.

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