Question

Даю 100 баллов! Тролейбус масою 20т рухається з прискоренням 1,5 м/с. Сила тяги тролейбуса 50 кН. Знайти коефіцієнт третя коліс об дорогу.Троллейбус массой 20т двигается с ускорением 1,5 м/с. Сила тяги троллейбуса 50 кН. Найти коэффициент третьих колес о дорогу.​

Answer 1

Відповідь не моя, але сподіваюсь що це воно

Answer 2

To find the coefficient of rolling friction between the third wheel of the trolleybus and the road, we can use the following formula:

Coefficient of rolling friction (μ) = (Force of rolling friction) / (Normal force)

Given information:

- Mass of the trolleybus (m) = 20 tons = 20,000 kg - Acceleration (a) = 1.5 m/s^2 - Force of traction (F) = 50 kN

Calculating the normal force:

The normal force (N) is the force exerted by the road on the trolleybus perpendicular to the surface. It is equal to the weight of the trolleybus.

Normal force (N) = mass (m) * acceleration due to gravity (g)

Using the approximate value of acceleration due to gravity as 9.8 m/s^2, we can calculate the normal force:

N = m * g

N = 20,000 kg * 9.8 m/s^2

N = 196,000 N

Calculating the force of rolling friction:

The force of rolling friction (Ff) is the force opposing the motion of the trolleybus due to the interaction between the third wheel and the road. It can be calculated using the formula:

Force of rolling friction (Ff) = μ * N

where μ is the coefficient of rolling friction.

Calculating the coefficient of rolling friction:

To find the coefficient of rolling friction (μ), we rearrange the formula:

μ = Ff / N

Substituting the given values, we have:

μ = (Force of rolling friction) / (Normal force)

μ = Ff / N

μ = (50 kN) / (196,000 N)

μ ≈ 0.2551

Therefore, the coefficient of rolling friction between the third wheel of the trolleybus and the road is approximately 0.2551.

Please note that the values used in this calculation are approximate and may vary depending on the specific conditions and characteristics of the trolleybus and the road surface.