Question

X1=3,4см,x2=-4,2cм,t1=3.0c,t2=5.1c Vcред-?

Answer 1

<V>=x1+x2/t1+t2

<V>=0,34+0,42/3+5,1=0,09 (м/с)

Answer 2

It's not entirely clear what you're asking for, but I'll assume you want to calculate the average velocity (Vcред) of an object that moves from position x1 = 3.4 cm to position x2 = -4.2 cm in a time interval t2 - t1 = 2.1 s.

The average velocity of the object is simply the displacement (change in position) divided by the time interval:

Vcред = (x2 - x1) / (t2 - t1)

Substituting the given values, we get:

Vcред = (-4.2 cm - 3.4 cm) / (5.1 s - 3.0 s)

Vcред = -7.6 cm / 2.1 s

Vcред ≈ -3.62 cm/s

Therefore, the average velocity of the object is approximately -3.62 cm/s. Note that the negative sign indicates that the object is moving in the negative direction (towards the left), as expected from the given positions.