Question

В прямоугольнике одна сторона длинее другой на 2 см а периметр равен 34см чему равна площадь этого прямоуголника

Answer 1

Problem Analysis

We are given a rectangle with one side longer than the other by 2 cm, and the perimeter of the rectangle is 34 cm. We need to find the area of the rectangle.

Solution

Let's assume the shorter side of the rectangle is x cm. Then the longer side will be (x + 2) cm.

The perimeter of a rectangle is given by the formula: perimeter = 2 * (length + width).

Given that the perimeter is 34 cm, we can write the equation as: 34 = 2 * (x + (x + 2))

Simplifying the equation: 34 = 2 * (2x + 2) 34 = 4x + 4 4x = 34 - 4 4x = 30 x = 30 / 4 x = 7.5

So, the shorter side of the rectangle is 7.5 cm, and the longer side is (7.5 + 2) = 9.5 cm.

The area of a rectangle is given by the formula: area = length * width.

Therefore, the area of this rectangle is: Area = 7.5 cm * 9.5 cm = 71.25 cm².

Answer: The area of the rectangle is 71.25 cm².