Question

Аквариум имеет форму прямоугольного параллепипеда. Его ширина 7.2 дм, что состовляет 80% его длины , а высота в 3 раза меньше длины.определите,сколько воды налито в аквариум, если она занимает 2/3(две третих) часть аквариума. пожалуйста, очень срочно!!!

Answer 1

Calculation of the Volume of the Aquarium

To determine the amount of water in the aquarium, we need to calculate the volume of the rectangular parallelepiped. We are given that the width of the aquarium is 7.2 dm, which is 80% of its length. Additionally, the height is three times smaller than the length.

Let's assign variables to the dimensions of the aquarium: - Width: w = 7.2 dm - Length: l - Height: h = (1/3) * l

To find the length, we can use the information that the width is 80% of the length. We can set up the equation:

w = 0.8 * l

Solving for l:

l = w / 0.8

Now that we have the length, we can calculate the height:

h = (1/3) * l

Finally, we can calculate the volume of the aquarium using the formula:

Volume = w * l * h

Let's substitute the values and calculate the volume.